| 12.4 [10 pts] |
- assume the material is plain carbon steel
- ΔT
= 297 in-lb
- Δτ = 49.9 ksi
|
| 12.12 [20 pts] |
- Fs = 3160 N
- τs
= 443 MPa
- use Su = 1225 MPa (but explain where it comes from)
- the
spring should return to its original length
|
|
12.21 [30 pts] |
- the spring mean diameter is different from the outer diameter
- use
Su = 1550 MPa and Ks = 1.06
(but explain where they come from)
- (a) Fmax = 122 N
- (b)
k = 3.22 N/mm
- (c) Lf = 61.9 mm
- (d) no buckling
should occur
|
| 12.29a,b
[40 pts] | - based
on clash allowance and Fmax, Fs = 712.5 N
- based
on the specified τs, CKw
= 8.93
- use C = 7.4 (but explain where it came from)
- (a)
D = 33.3 mm; N = 2.44; Ls = 20.0 mm; Lf
= 35.8 mm
- (b) no buckling should occur; no surge should occur;
- plot the τmax- τmin
diagram with the load point and load line
- SF = 1.1
|